.4x^2+80x=0

Solution for .4x^2+80x=0 equation:

.4x^2+80x=0

a = .4; b = 80; c = 0;
Δ = b2-4ac
Δ = 802-4·.4·0
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80}{2*.4}=\frac{-160}{0.8}
=-200
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80}{2*.4}=\frac{0}{0.8}
=0
$